In following number series, two terms have been put within brackets. Choose the appropriate option

Choose the appropriate option 3, 10, 29, (66), (127), 218

Choose the appropriate option 3, 10, 29, (66), (127), 218

The sequence is 1

Clearly, both the terms 66 and 127 are correct..

Look at this series: 2, 4, 6, 8, 10, . . .

What number should come next?

What number should come next?

This is a simple addition series.

Each number increases by 2.

Like -

First number is 2

Second number = 2 + 2 =4

Third number = 4 + 2 = 6

Fourth number = 6 + 2 = 8

Fifth number = 8 + 2 = 10 and

Sixth number = 10 + 2 = 12

Hence, The answer is (b) 12..

In alphabet series, some alphabets are missing which are given in that order as one of the alternatives below it. Choose the correct alternative.

ba _ b _ aabb _ a _ _ a _ bb

The series is baab / baab / baab / baab / b. Thus, the pattern baab is repeaated

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In following questions, one term in number series is incorrect.

Find out the incorrect number 10, 14, 28, 32, 64, 68, 132

Find out the incorrect number 10, 14, 28, 32, 64, 68, 132

Alternately, the numbers are increased by four and doubled to get the next number>

Thus, 10 + 4 = 14;

14 * 2 = 28;

28 + 4 = 32;

32 * 2 =64 and so on.

So, 132 is wrong and must be replaced by (68 * 2) i.e. 136..

If a boat travels with speed 10 kilometre per hour in still water and speed of stream is 5 kilometre per hour what would be the time taken by boat to go 60 km downstream?

Thus, downstream speed=(x+y)km/he=10+5=15 km/hr

We have,

Time=distance/speed

Time taken by a boat to travel 60 km downstream will be equal to the ratio of distancees travel to downstream speed.

Time taken by a boat= 60/15=4 hr

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The sum of even numbers between 1 and 31 is:

Let Sn = (2 + 4 + 6 + ... + 30). This is an A.P. in which a = 2, d = 2 and l = 30

Let the number of terms be n. Then,

a + (n - 1)d = 30

2 + (n - 1) x 2 = 30

n = 15.

Sn =n/2(a + l)=15/2x (2 + 30) = (15 x 16) = 240.

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In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. J2Z, K4X, 17V, ?, H16R, M22P

The first letters in odd numbered terms from series J, I, H and in even numbered terms from the series K, L, M. The sequence followed by the numbers is + 2, + 3, + 4, + 5, + 6. The third letter of each term is moved two steps backward to obtain the third letter of the next term.

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In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. DEF, HIJ, MNO, ?

The letters in each term are consecutive. There is a gap of one letter between the last letter of the first term and the first letter of the second term and a gap of two letters between the last letter of the second term and the first letter of third term. So, there would be a gap of three letters between the last letter of the third term and the first letter of the fourth term.

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What is the unit digit in(795 - 358)?

Unit digit in 795 = Unit digit in [(74)23 x 73]

= Unit digit in [(Unit digit in(2401))23 x (343)]

= Unit digit in (123 x 343)

= Unit digit in (343)

= 3

Unit digit in 358 = Unit digit in [(34)14 x 32]

= Unit digit in [Unit digit in (81)14 x 32]

= Unit digit in [(1)14 x 32]

= Unit digit in (1 x 9)

= Unit digit in (9)

= 9

Unit digit in (795 - 358) = Unit digit in (343 - 9) = Unit digit in (334) = 4.

So, Option B is the answer.

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In following alphabet series , one term missing as shown by question mark . Choose missing term from options.

A, Z, X, B, V, T, C, R, ?, ?

The first, fourth and seventh letters are in alphabetical order. So, tenth letter would be the letter after C i.e. D. Also, the second and third letters are alternate and in reverse order and so are the fifth and sixth letters and the eighth and ninth letters.

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