There is a family of 6 persons A, B, C, F, E and F .

They are lawyer, doctors, Teacher,salesman, Engineer and accountant .there are two married couple in the family. D, salesman, is married to lady teacher.the doctor is married to the lawyer . F , unmarried Engineer.A is the grand mother of F. Which of the following is one of the couples?

C is the daughter in law of A who is the Grand Mother of Means C is the mother of F. But F is the son of B. So, B is C, husband.But C, the lawyer, is married to the doctor. So, B is the doctor. F, the accountant, will be the son of B and C. E is the unmarried engineer. So, the other married couples can be that of grandmother of F i. e., A and D. But D, the salesman, is married to the lady teacher. Song, d, the salesman, is the grandfather of f, father of B and the husband of A the lady teacher. The two couple are C and B, and D and A which is nown among the choices..

A + B means A is the daughter of B ;

A x B means A is the son of B and

A - B means A is the wife of B.

If Z x T - S x U + P, what is U to Z.

Option: (B)

Pointing to a man in photograph, a woman said, His brother father in the only son of my grandfather. How is the woman related to the man in the photograph?

Blood relation analysis.

Only son of women grandfather= woman father

Man's brother father =man father

so woman is man's sister

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The average of 5 consecutive even numbers is 34. What is the difference between the highest and lowest number.

Let's 5 consecutive even numbers are:

2, 4, 6, 8, 10.

Lowest term is 2 and highest is 10

10 - 2 = 8

So, difference of 8 will remain the same in the consecutive series numbers.

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In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. 2Z5, 7Y7, 14X9, 23W11, 34V13, ?

The first numbers in the terms follow the sequence + 5, + 7, + 9, + 11, + 13. The middle letters form the series Z, Y, X, W, V, U.

The last numbers from the series 5, 7, ,9 , 11, 13, 15.

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A man and his wife have three sons, and every
of the sons have a sister. How many are there in the family?

Option (C)

There is only 1 girl since it says that every sons has 'a' sister, if there's only 1 girl. She will be a sister to all the three sons.

So 3 sons + 1 sister + both the parents = 6 members in the family.

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family consists of six members P, Q, R, X, Y and Z. Q is the son of R but R is
not mother of Q. P and R are a married couple. Y is the brother of R. X is the
daughter of P. Z is the brother of P. How is Q related to X ?

Option (C)

Q is the son of R but R is not the mother. So, R is the father of Q. P is married to R. So, P is the wife of R and the mother of Q. X is the daughter of P and hence of R and so she is the sister of Q. Y is the brother of R and Z is the brother of P. X is the sister of Q who is a male. So, Q is brother of X.

.. In following questions, a sequence of groups of alphabets and numbers is provided with one term missing , Choose the missing term from options. LXF, MTJ, NPN, OLR, ?

The first letter of each term is moved one step forward, the second letter is moved four steps backward and the third letter is moved four steps forward to obtain the corresponding letters of the next term.

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A + B means A is the son of B;

A - B means A is the wife of B;

A x B means A is the brother of B;

A Ã· B means A is the mother of B; and

A = B means A is the sister of B.

What does P = R Ã· Q mean?

Option (A)

P = R Ã· Q means P is the sister of R who is the mother of Q i.e. P is the aunt of Q.

So, the answer is (a).

In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class ?

Let the number of boys and girls participating in sports be 3x and 2x respectively.

Then, 3x = 15 or x = 5.

So, number of girls participating in sports = 2x = 10.

Number of students not participating in sports = 60 - (15 + 10) = 35.

Let number of boys not participating in sports be y.

Then, number of girls not participating in sports = (35 -y).

Therefore (35 - y) = y + 5 , 2y , 30 , y = 15.

So, number of girls not participating in sports = (35 - 15) = 20.

Hence, total number of girls in the class = (10 + 20) = 30.

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