# Work, Profit & Loss Practice Questions & Tests

#### Question No 1

Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is

Solution!
Cost Price (C.P.) = (4700 + 800) = Rs. 5500! !Selling Price (S.P.) = Rs. 5800! !Gain = (S.P.) - (C.P.) = (5800 - 5500) = Rs. 300! !Gain % = (300/5500) * 100 = 60/5 %.

#### Question No 2

By selling a car for Rs. 495000 an agent gains 10%. What was his cost?

Solution!
Let cost price of the car is x.!10% of x = 10x/100 = x/10! !Now!495000 - (x/10) = x!4950000 - x = 10x!4950000 = 11x!x = 450000.

#### Question No 3

A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?

Solution!
S.P. = 85% of Rs. 1400 =(85/100)*1400!=Rs. 1190.

Solution!

Solution!

Solution!
Let cost price of the article is x.!12% of x = 12x/100 = 3x/25! !Now!84 - (3x/25) = x!2100 - 3x = 25x!2100 = 28x!x = 75! !Hence cost price of the article is $75.. #### Question No 11 A shopkeeper bought an article for$120 and sold at profit of 10%. What is selling price of the article?

Solution!
10% of 120!= (120*10)/100 = 12! !Selling price = 120+12 = 132.

#### Question No 12

A can do a certain work in the same time in which B and C together can do it.If A and B together could do it in 10 days and C alone in 50 days,then B alone could do it in

Solution!
(A + B)'s 1 day's work = 1/10! !C's 1 day's work = 1/50! !(A + B + C)'s 1 day's work = (1/10 + 1/50) = 6/50 = 3/25...(1)! !A's 1 day's work = (B + C)'s 1 day's work .... (2)! !From (1) and (2), we get!2 * (A's 1 day's work) = 3/25! !A's 1 day's work = 3/50! !So, B's 1 day's work (1/10 - 3/50) = 2/50 = 1/25! !Hence, B alone could do the work in 25 days..

#### Question No 13

A takes twice as much time as B or thrice as much time as C to finish a piece of work.Working together,they can finish the work in 2 days.B can do the work alone in

Solution!
Suppose A, B and C take x, x/2, x/3 days respectively to finish the work.! !Then,!(1/x + 2/x + 3/x) = 1/2!6/x = 1/2!x=12! !So, B takes (12/2) = 6 days to finish the work..

#### Question No 14

A is thrice as good as a workman as B and therefore is able to finish a job in 60 days less than B.Working together,they can do it in

Solution!
Ratio of times taken by A and B = 1/3! !The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.! !If difference of time is 2 days, B takes 3 days.! !If difference of time is 60 days, B takes (3/2 * 60) = 90 days! !So, A takes 30 days to do the work.! !A's 1 day's work = 1/30! !B's 1 day's work = 1/90! !(A + B)'s 1 day's work = (1/30 + 1/90) = 4/90 = 2/45! !Hence, A and B together can do the work in 45/2 = 22.5 days.

#### Question No 15

Ali sold a house at a loss of 15% for Rs. 382500. What was the cost price of the house?

Solution!
Let cost price of the house is x.!15% of x = 15x/100 = 3x/20! !Now!(3x/20)+382500 = x!3x + 7650000 = 20x!7650000 = 17x!x = 450000!Hence cost price of the house is Rs. 450000.

#### Question No 16

A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?

Solution!
Whole work is done by A in (20 * 5/4) = 25 days! !Now, (1 - 4/5) i.e., 1/5 work is done by A and B in 3 days.! !Whole work will be done by A and B in (3 x 5) = 15 days.! !A's 1 day's work = 1/25!(A + B)'s 1 day's work = 1/15! !So, B's 1 day's work = (1/15 - 1/25) = 4/150 = 2/75! !Hence, B alone would do the work in 75/2 = 37.5 days..

#### Question No 17

9 excavators working 10 hours a day remove 2500 cubic feet of earth in 3 days. How many excavators working 6 hours a day are required to remove 5000 cubic feet of earth in 2 days?

Solution!
Let x excavators are required.!As excavators are inversely proportional to hours and days and directly proportional to work progress so!x/9 = (10/6)*(5000/2500)*(3/2)!x = 45! !Hence 45 excavators are required to remove 5000 cubic feet of earth..

#### Question No 18

Price of a car increased from $400000 to$420000. What is the percentage increase?

Solution!
Increase in price = 420000 - 400000! = 20000! !Percentage increase = (20000/400000)*100! = 5%.

#### Question No 19

A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in

Solution!
(A + B + C)'s 1 day's work = 1/6! !(A + B)'s 1 day's work = 1/8! !(B + C)'s 1 day's work = 1/12! !So, (A + C)'s 1 day's work = (2* 1/6) - (1/8 + 1/12)!= (1/3 - 5/24) = (3/24) = 1/8! !So, A and C together will do the work in 8 days..

Solution!
Let cost price of the house is x.!15% of x = 15x/100 = 3x/20! !Now!494500 - (3x/20) = x!9890000 -3x = 20x!9890000 = 23x!x = 430000! !Hence cost price of the house is $430000.. #### Question No 28 Value of a house decreased from$250000 to $200000. What is the percentage decrease in the value? #### Select the correct answer Solution! Decrease in value of house = 250000 - 200000 = 50000! !Percentage decrease = (50000/250000)*100 = 20%. #### Question No 29 With an increase of 12% salary of Ali became Rs13440. What was his salary before increase? #### Select the correct answer Solution! Let before increase Ali's salary was x.!12% of x = 12x/100 = 3x/25! !Now!13440 - 3x/25 = x!336000 - 3x = 25x!336000 = 28x!x = 12000! !Hence Ali's salary before increase was Rs. 12000. #### Question No 30 Cost price of a camera was$430 and it was sold at profit of 16%. What is its selling price?

Solution!
16% of 430 = (430*16)/100 = 68.8! !Selling price = 430 + 68.8 = 498.8.

#### Question No 32

A works twice as fast as B.If B can complete a work in 12 days independently,The number of days in which A and B can together finish the work in

Solution!
Ratio of rates of working of A and B = 2/1! !So, ratio of times taken = 1/2! !B's 1 day's work = 1/12! !A's 1 day's work = 1/6!(2 times of B's work)! !(A + B)'s 1 day's work = (1/6 + 1/12) = 1/4! !So, A and B together can finish the work in 4 days..

#### Question No 33

Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is

Solution!
Suppose, number of articles bought =L.C.M. of 6 and 5!= 30! !C.P. of 30 articles = (5/6) * 30 = Rs. 25! !S.P. of 30 articles = (6/5)*30! = Rs. 36! !Hence, Gain % = (11/25) * 100 = 44%.

#### Question No 34

Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is

Solution!
Ratio of times taken by Sakshi and Tanya = 125/100 = 5/4! !Suppose Tanya takes x days to do the work.! !5/4 = 20/x!x = (4*20)/5! !x = 16 days.! !Hence, Tanya takes 16 days to complete the work..

#### Question No 35

Twenty women can do a work in sixteen days. Sixteen men can complete the same work in fifteen days. What is the ratio between the capacity of a man and a woman?

Solution!
(20 x 16) women can complete the work in 1 day.! !So, woman's 1 day's work = 1/320! !(16 x 15) men can complete the work in 1 day.! !So, 1 man's 1 day's work = 1/240! !So, required ratio = (1/240) / (1/320)!= (1/3) / (1/4) = 4/3.

#### Question No 36

A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?

Solution!
Ratio of times taken by A and B = 100/130 = 10/13! !Suppose B takes x days to do the work.! !Then, 10/13 = 23/x!x = (23*13)/10!x = 299/10! !A's 1 day's work = 1/23! !B's 1 day's work = 10/299! !(A + B)'s 1 day's work = (1/23 + 10/299) = 23/299 = 1/13! !Therefore, A and B together can complete the work in 13 days..

#### Question No 37

In a ship the provisions are sufficient for 800 men for 50 days. How long will these be sufficient for if there would have been 200 more men?

Solution!
Let provisions will be sufficient for 200 men for x days.!As men and days are inversely proportional to each other so!x/50 = 800/1000!x = 40! !Hence provisions will be sufficient for 200 men for 40 days..

An article was bought for $300 and sold at a loss of 8%. What is the selling price of the article? #### Select the correct answer Solution! 8% of 300!= (300*8)/100 = 24! !Selling price = 300-24 = 276. #### Question No 39 A can do a work in 15 days and B in 20 days.If they work on it together for 4 days,then the fraction of the work that is left is #### Select the correct answer Solution! A's 1 day's work = 1/15! !B's 1 day's work = 1/20! !(A + B)'s 1 day's work = (1/15 + 1/20) = 7/60! !(A + B)'s 4 day's work = (7/60 * 4) = 7/15! !Therefore, Remaining work = (1 - 7/15) = 8/15. #### Question No 40 Price of an article increased from$50 to $55. What is the percentage increase? #### Select the correct answer Solution! Increase in price = 55-50 = 5!Percentage increase = (5/50)*100! =10%. #### Question No 41 The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is #### Select the correct answer Solution! Let!C.P. of each article be Re. 1 C.P. of x articles = Rs. x.! !S.P. of x articles = Rs. 20.! !Profit = Rs. (20 - x)! !So, (20-x)/x * 100 = 25!2000 - 100x = 25x!125x = 2000! !Hence, x = 16. #### Question No 42 If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be #### Select the correct answer Solution! Let, 1 man's 1 day's work = x!and 1 boy's 1 day's work = y! !Then, 6x + 8y = 1/10!and 26x + 48y = 1/2! !Solving these two equations, we get!x = 1/100!and y = 1/200! !(15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4! !Hence, 15 men and 20 boys can do the work in 4 days.. #### Question No 43 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it? #### Select the correct answer Solution! Let, 1 man's 1 day's work = x!and!1 woman's 1 day's work = y! !Then, 4x + 6y = 1/8 nd 3x + 7y = 1/10! !Solving the two equations, we get!x = 11/400!y = 1/400! !So, One woman's 1 day's work = 1/400! !10 women's 1 day's work = (1/400 * 10) = 1/40! !Hence, 10 women will complete the work in 40 days.. #### Question No 44 In a fort there is enough food sufficient for 1200 men for 10 days. How long the food would have last for if there would have been 1000 men. #### Select the correct answer Solution! Let food will last for x days.!As men and days are inversely proportional to each other so!x/10 = 1200/1000!x = 12! !Hence food will last for 12 days if there were 1000 men.. #### Question No 45 A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%? #### Select the correct answer Solution! C.P. of 6 toffees = Re. 1! !S.P. of 6 toffees = 120% of Re. 1 = Rs. 6/5! !For Rs. 6/5,!toffees sold = 6.! !For Re. 1, toffees sold = (6 * 5/6) = 5. #### Question No 46 What will be the selling price of an article that was bought for$350 and sold at a loss of 14%?

Solution!
14% of 350!(350*14)/100 = 49! !selling price of the article = 350 - 49 = 301.

#### Question No 47

A, B and C can complete a piece of work in 24, 6 and 12 days respectively.Working together,they will complete the same work in

Solution!
As we know that!If A can do a piece of work in n days, then A's 1 day's work = 1/n! !(A + B + C)'s 1 day's work = (1/24 + 1/6 + 1/12) = 7/24! !If A's 1 day's work = 1/n then,!A can finish the work in 'n' days.! !So, all the three together will complete the job in (24/7) days..

What will be the selling price of an article that was bought for $475 and sold at a loss of 12%? #### Select the correct answer Solution! 12% of 475!=(475*12)/100 = 57! !Selling price = 475-57 = 418. #### Question No 49 If selling price is doubled, the profit triples. Find the profit percent. #### Select the correct answer Solution! Let! C.P. be Rs. x and S.P. be Rs. y.! !Then,! 3(y - x) = (2y - x)!y = 2x! !Profit = Rs. (y - x) = Rs. x! !Profit % = (x/x)*100 = 100%. #### Question No 50 A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit? #### Select the correct answer Solution! C.P. = (100/122.5) * 392!= (1000/1225) * 392!= Rs. 320! !Hence, Profit = Rs. (392 - 320) = Rs. 72.. #### Question No 51 John's income increased from$12000 to $14400. What is percentage increase in his income? #### Select the correct answer Solution! Increase in income = 14400 - 12000 = 2400! !Percentage increase = (2400/12000)*100 = 20%. #### Question No 52 By selling an article for$200 shopkeeper looses 20%. What is cost price of the article?

Solution!
Let cost price of the article is x.! !20% of x = (x*20)/100 = x/5! !Now!(x/5) + 200 = x!x+1000 = 5x!4x = 1000!x = 250! !Hence cost price of the article is 250..

#### Question No 53

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in

Solution!
(B + C)'s 1 day's work = (1/9 + 1/12) = 7/36! !Work done by B and C in 3 days = (7/36 * 3)!= 7/12! !Remaining work = (1 - 7/12)!= 5/12! !Now, 1/24 work is done by A in 1 day.! !So, 5/12 work is done by A in (24 * 5/12) = 10 days..

#### Question No 54

A salesman bought a pen for Rs. 100 and sold it for Rs. 110. What is his profit percent?

Solution!
Profit = 110 - 100 = 10! !Profit percentage = (10/100)*100 = 10%.

#### Question No 55

A farmer bought a cow for Rs. 14000 and sold it for Rs. 15400. Find his profit percentage.

Solution!
Profit = 15400 - 14000 = 1400! !Profit percentage = (1400/14000)*100 = 10%.

#### Question No 57

Price of a fuel increased by 10% during budget. If its price before budget was Rs. 55 per liter what is its price after the budget?

Solution!
10% of 55 = (55*10)/100 = 5.5! !Price of fuel after butget = 55+5.5 = 60.5.

#### Question No 58

Ali bought a house for $450000 and sold it for$500000. What is his profit percentage?

Solution!
Profit = 500000-450000 = 50000! !Profit percentage= (50000/450000)*100 = 11.11%.

#### Question No 59

What will be the selling price of an article that was bought for \$1150 and sold at profit of 6%?

Solution!
6% of 1150!= (1150*6)/100 = 69! !Selling price = 1150+69 = 1219.

#### Question No 60

A and B can do a job together in 7 days. A is 7/4 times as efficient as B.The same job can be done by A alone in